Calculating ASW of a silver coin.

Hi All,

If I have a coin "1978 Panama 1 Balboa", I know that it is sterling silver "0.925" and it's weight is 26.73 Grams.

how can I calculate the actual silver content of the coin.

Thanks.

 

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You have 24.72525 grams of silver. .925*26.73. Divide it by 31.1034 and you have .7949 ounces of pure silver.

Chris

 

http://www.ngccoin.com/poplookup/WorldCoinPrices.aspx?category=6259&worldcoinid=22268

In any case, the formula for ASW is:

(Gram weight) * (fineness) * 0.0321507466 = ASW in Troy ounces.

Edit: It is sterling. I was wrong about the fineness.

 

.925 * 26.73g = 24.72525 grams

 

I found the answer 5 seconds after posting the question ..

Next time I shall do more research before asking ..

Thanks

 

Why did you use 32.15? Isn't the conversion rate 31.1034?

 

Lol talk about overkill. We DESTROYED the question guys!

 

By golly, when CTers answer a question, it knows it's been answered....and it better STAY answered too!

 

You are right, picked up the number of troy ounces in a kilogram instead. I will fix the above post.

 

Thanks guys

NorthKorea:The coin was done by the Franklin Mint and it is 0.925 Stirling Silver.

Now I really want a panama 1978 proof set .. it has ~ 6 oz. ASW and looks great.